A mass m₁ of 5.00 kg slides on a frictionless surface.This mass is connected to another mass m₂ by a massless string over a frictionless pulley.The masses are held motionless and then released.Mass m₂ accelerates downward at 4.10 m/s².What is the mass of m₂? A)17.0 kg B)3.59 kg C)5.00 kg D)6.96 kg E)1.47 kg

Question

Quizplus · Accepted Answer

Since the system is frictionless, the tension in the string is constant and equal to the force needed to accelerate both masses. Therefore, we can use Newton's second law to write the equations of motion for the two masses: m1*a = T m2*g - T = m2*a where a is the acceleration of m2, T is the tension in the string, m1 is the mass of m₁, m2 is the mass of m₂, and g is the acceleration due to gravity. We are given that m2 accelerates downward at 4.10 m/s^2, so we can substitute this value into the second equation: m2*9.81 N/kg - T = m2*4.10 m/s^2 Solving for T: T = m2*5.71 N/kg Substituting this into the first equation: m1*a = m2*5.71 N/kg We are given that m1 = 5.00 kg, so we can solve for m2: m2 = m1*a/5.71 N/kg = 5.00 kg * 4.10 m/s^2 / 5.71 N/kg = 3.59 kg Therefore, the answer is B) 3.59 kg.

A Mass M1 of 5

A Mass M₁ of 5