A skier leaves a ski jump with a horizontal velocity of 21.0 m/s (and no vertical velocity component).The skier lands three seconds later.What is the magnitude of the horizontal component of the skier's displacement during the jump
A)32.2 m
B)63.0 m
C)44.1 m
D)51.8 m

Question

Quizplus · Accepted Answer

The horizontal component of the skier's displacement can be calculated using the formula $d = vt$, where $d$ is displacement, $v$ is the horizontal velocity, and $t$ is the time. Given $v = 21.0 \, \text{m/s}$ and $t = 3 \, \text{s}$, the displacement is $d = 21.0 \, \text{m/s} \times 3 \, \text{s} = 63.0 \, \text{m}$.

A Skier Leaves a Ski Jump with a Horizontal Velocity