You toss a stone vertically upward and it reaches a maximum height of 2.06 m above the launch point.The initial velocity of the stone was
A)336 m.
B)215 m.
C)125 m.
D)6.36 m.

Question

Quizplus · Accepted Answer

The maximum height reached by the stone can be found using the formula:

h = (v^2)/(2g)

where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the given values, we get:

2.06 = (v^2)/(2*9.8)

Solving for v, we get:

v = sqrt(2 * 9.8 * 2.06)

v ≈ 6.36 m/s

Therefore, the initial velocity of the stone was 6.36 m/s, which corresponds to choice D.

You Toss a Stone Vertically Upward and It Reaches a Maximum