A person fires a warning shot out of handgun.If the bullet leaves the gun with an initial speed of 305 m/s and travels straight upward,how much time does the person firing the gun have to move out of the way before the bullet hits the ground? (Ignore the effects of air resistance.)
A)15.6 s
B)31.1 s
C)62.2 s
D)None are correct.

Question

Quizplus · Accepted Answer

The time it takes for an object to reach its maximum height (in this case, the bullet's highest point before falling back down) can be found using the equation:
t = v/g
where v is the initial velocity (305 m/s) and g is the acceleration due to gravity (-9.8 m/s^2). 
Plugging in the values, we get:
t = 305/-9.8 = 31.12 s (rounded to two decimal places)
Since the bullet travels straight up and then falls back down, the total time it takes to hit the ground is twice the time it takes to reach the maximum height:
2t = 62.24 s
Therefore, the person firing the gun has 62.24 seconds to move out of the way before the bullet hits the ground.

A Person Fires a Warning Shot Out of Handgun