At time,t = 0 s,car A is at rest at the origin of the coordinate system and car B is moving due East at a constant velocity of 20 m/s.When car B is 50 m west of car A,car A starts to move at a constant acceleration of 2 m/s² due East.How far from the origin has car A moved when car B overtakes car A? A)20.0 m B)8.58 m C)14.3 m D)2.0 m E)4.36 m

Question

Quizplus · Accepted Answer

Let's first find the time it takes for car B to catch up to car A. We can use the equation:

d = vt

where d is the distance car B needs to cover to catch up to car A (which is 50 m), v is car B's velocity (20 m/s), and t is the time it takes.

50 = 20t

t = 2.5 s

Now that we know the time, we can find how far car A has traveled using the equation:

d = vit + 1/2at^2

where vi is car A's initial velocity (0 m/s), a is car A's acceleration (2 m/s^2), and t is the time it takes.

d = 0 + 1/2(2)(2.5)^2

d = 8.75 m

Therefore, car A has moved 8.75 m from the origin when car B overtakes car A. The best choice is B).

At Time,t = 0 S,car a Is at Rest at the Origin