How many moles of water, O, are produced from the reaction of 16 grams methane, C , with an unlimited supply of oxygen, . How many grams of O is this? C + 2 → C + 2 O

Question

How many moles of water,  O, are produced from the reaction of 16 grams methane, C  , with an unlimited supply of oxygen,  . How many grams of  O is this? C  + 2  → C  + 2  O

Quizplus · Accepted Answer

1. First, we need to balance the chemical equation:
    CH4 + 2O2 → CO2 + 2H2O

2. Then, we need to calculate the number of moles of methane:
    molar mass of CH4 = 12.01 + 4(1.01) = 16.05 g/mol
    moles of CH4 = 16 g / 16.05 g/mol = 0.997 moles

3. According to the balanced equation, 1 mole of CH4 yields 2 moles of H2O. 
    moles of H2O = 2 x 0.997 = 1.994, which is approximately 2 moles

4. Finally, we can calculate the mass of water formed:
    molar mass of H2O = 2(1.01) + 16.00 = 18.02 g/mol
    mass of H2O = 2 mol x 18.02 g/mol = 36.04 g, which is approximately 36 grams.

Thus, the best choice is C.

How Many Moles of Water, O, Are Produced from the Reaction