A train starts from rest and accelerates uniformly until it has traveled 2.1 km and acquired a forward velocity of $ 24 \mathrm{~m} / \mathrm{s} $ The train then moves at a constant velocity of $ 24 \mathrm{~m} / \mathrm{s} $ for 400 s. The train then slows down uniformly at $ 0.065 \mathrm{~m} / \mathrm{s}^{2} $ until it is brought to a halt. The distance traveled by the train while slowing down is closest to
A) 4.4 km.
B) 4.2 km.
C) 4.0 km.
D) 3.8 km.
E) 3.6 km.

Question

Quizplus · Accepted Answer

The distance traveled while slowing down can be calculated using the formula $ v^2 = u^2 + 2as $, where $ v = 0 $, $ u = 24 \, \text{m/s} $, and $ a = -0.065 \, \text{m/s}^2 $. Solving for $ s $ gives approximately 4.4 km.

A Train Starts from Rest and Accelerates Uniformly Until It 24 m/s 24 \mathrm{~m} / \mathrm{s} 24 m/s

A Train Starts from Rest and Accelerates Uniformly Until It $24 \mathrm{~m} / \mathrm{s}$