A driver in a $1000 - \mathrm { kg }$ car traveling at $24 \mathrm {~m} / \mathrm { s }$ slams on the brakes and skids to a stop. If the coefficient of friction between the tires and the level road is 0.80, how long will the skid marks be?
A) 37 m
B) 30 m
C) 46 m
D) 34 m

Question

Quizplus · Accepted Answer

The stopping distance can be calculated using the formula $d = \frac{v^2}{2\mu g}$, where $v = 24 \, \mathrm{m/s}$, $\mu = 0.80$, and $g = 9.8 \, \mathrm{m/s^2}$. Plugging in the values gives $d = \frac{24^2}{2 \times 0.80 \times 9.8} = 37 \, \mathrm{m}$.

A Driver in A 1000−kg1000 - \mathrm { kg }1000−kg Car Traveling At

A Driver in A $1000 - \mathrm { kg }$ Car Traveling At