A force of $16.88 \mathrm {~N}$ is applied tangentially to a wheel of radius 0.340 m and causes an angular acceleration of 1.20 rad/s². What is the moment of inertia of the wheel? A) 4.78 kg ? m² B) 3.59 kg ? m² C) 5.98 kg ? m² D) 7.17 kg ? m²

Question

Quizplus · Accepted Answer

The torque τ is given by τ = r * F = 0.340 m * 16.88 N = 5.7392 Nm. The moment of inertia I is τ / α = 5.7392 Nm / 1.20 rad/s² = 4.7827 kg·m², which rounds to 4.78 kg·m².

A Force Of 16.88 N16.88 \mathrm {~N}16.88 N Is Applied Tangentially to a Wheel of Radius 0

A Force Of $16.88 \mathrm {~N}$ Is Applied Tangentially to a Wheel of Radius 0