A Carnot engine operates between two reservoirs with unknown temperatures. If the Carnot engine operates at $67 \%$ efficiency, what is the ratio of the absolute temperatures of the reservoirs, T_c/T_h? A) 0.33 B) 0.0012 C) 0.0025 D) 0.67

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Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by $1 - \frac{T_c}{T_h}$. If the efficiency is 67%, then $1 - \frac{T_c}{T_h} = 0.67$. Solving for $\frac{T_c}{T_h}$, we get $\frac{T_c}{T_h} = 0.33$.

A Carnot Engine Operates Between Two Reservoirs with Unknown Temperatures 67%67 \%67%

A Carnot Engine Operates Between Two Reservoirs with Unknown Temperatures $67 \%$