What is the average translational kinetic energy of an ideal gas at $819 \mathrm {~K} \text { ? }$ The Boltzmann constant is 1.38 × 10^-23 J/K. A) 1.70 x 10^-20 J B) 5.65 x 10^-21 J C) 1.13 x 10^-17 J D) 3.77 x 10^-19 J

Question

Quizplus · Accepted Answer

The average translational kinetic energy of an ideal gas is given by $\frac{3}{2}kT$. Substituting $k = 1.38 \times 10^{-23} \, \text{J/K}$ and $T = 819 \, \text{K}$, we get $\frac{3}{2} \times 1.38 \times 10^{-23} \times 819 = 1.70 \times 10^{-20} \, \text{J}$.

What Is the Average Translational Kinetic Energy of an Ideal 819 K ? 819 \mathrm {~K} \text { ? }819 K ?

What Is the Average Translational Kinetic Energy of an Ideal $819 \mathrm {~K} \text { ? }$