A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110 kPa.How much work is done by the gas during this expansion?
A)3.85 kJ
B)10.4 kJ
C)3850 kJ
D)10.4 MJ
E)3.85 MJ

Question

Quizplus · Accepted Answer

The work done by a gas during expansion at constant pressure can be calculated using the formula $W = P \Delta V$, where $W$ is the work done, $P$ is the pressure, and $\Delta V$ is the change in volume. Here, $\Delta V = 65.0\,L - 30.0\,L = 35.0\,L$, and since $1\,L \cdot kPa = 1\,J$, the work done is $110\,kPa \times 35.0\,L = 3850\,J = 3.85\,kJ$.

A Gas Expands from an Initial Volume of 30