In a two-slit experiment, monochromatic coherent light of wavelength 600 nm passes through a pair of slits separated by 2.20 x $10 ^ { - 5 }$ m. At what angle away from the centerline does the first bright fringe occur?
A) 1.56°
B) 2.22°
C) 3.12°
D) 4.70°
E) 6.24°

Question

Quizplus · Accepted Answer

The equation for the location of the bright fringes in a two-slit experiment is given by:

$$d\sin{	heta} = m\lambda$$

Where:
- d is the distance between the two slits
- θ is the angle between the centerline and the direction of the fringe
- m is the order of the fringe (m=1 for the first bright fringe)
- λ is the wavelength of the light

Substituting the given values:

$$2.20	imes10^{-5}	imes \sin{	heta} = 1	imes 600	imes 10^{-9}$$

Simplifying and solving for θ:

$$	heta = \sin^{-1}\left(\frac{\lambda}{d}ight) = \sin^{-1}\left(\frac{600 	imes 10^{-9} m}{2.20	imes10^{-5} m}ight) = 1.56°$$

Therefore, the first bright fringe occurs at an angle of 1.56° away from the centerline, which corresponds to choice A).

In a Two-Slit Experiment, Monochromatic Coherent Light of Wavelength 600 10−510 ^ { - 5 }10−5

In a Two-Slit Experiment, Monochromatic Coherent Light of Wavelength 600 $10 ^ { - 5 }$