In a two-slit experiment, a third-order bright fringe is observed at an angle of 7.10° away from the centerline. If the wavelength of light is 595 nm, how far apart are the two slits?
A) 1.44 × $10 ^ { - 5 }$ m
B) 1.07 × $10 ^ { - 5 }$ m
C) 2.12 × $10 ^ { - 5 }$ m
D) 2.53 × $10 ^ { - 5 }$ m
E) 3.76 × $10 ^ { - 5 }$ m

Question

Quizplus · Accepted Answer

The correct answer is A.The distance between the two slits can be calculated using the formula:$$d = \frac{m\lambda}{sin	heta}$$where:* d is the distance between the slits* m is the order of the bright fringe* λ is the wavelength of light* θ is the angle of the bright fringe from the centerlineIn this case, we have:* m = 3* λ = 595 nm = 5.95 × 10^-7 m* θ = 7.10° = 0.123 radiansSubstituting these values into the formula, we get:$$d = \frac{3 	imes 5.95 	imes 10^{-7} m}{sin 0.123 radians} = 1.44 	imes 10^{-5} m$$Therefore, the distance between the two slits is 1.44 × 10^-5 m.

In a Two-Slit Experiment, a Third-Order Bright Fringe Is Observed 10−510 ^ { - 5 }10−5

In a Two-Slit Experiment, a Third-Order Bright Fringe Is Observed $10 ^ { - 5 }$