Two electrons are $20.0 \mathrm {~mm}$ apart at closest approach. What is the magnitude of the maximum electric force that they exert on each other?
(e = 1.60 × 10^-19 C, k = 1/4πε₀ = 9.0 10⁹ N ∙ m²/C²)

Question

Two electrons are

20.0 \mathrm {~mm}

apart at closest approach. What is the magnitude of the maximum electric force that they exert on each other?
(e = 1.60 × 10^-19 C, k = 1/4πε₀ = 9.0 10⁹ N ∙ m²/C²)

Quizplus · Accepted Answer

The electric force between two charges is given by Coulomb's law: $ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} $. Substituting the given values: $ F = \frac{9.0 \times 10^9 \cdot (1.60 \times 10^{-19})^2}{(0.020)^2} $, which calculates to approximately $ 5.8 \times 10^{-25} $ N.

Two Electrons Are 20.0 mm20.0 \mathrm {~mm}20.0 mm Apart at Closest Approach

Two Electrons Are $20.0 \mathrm {~mm}$ Apart at Closest Approach