A 6.9 μC negative point charge has a positively charged particle in an elliptical orbit about it. If the mass of the positively charged particle is $1.0 \mu \mathrm { g }$ and its distance from the point charge varies from $4.0 \mathrm {~mm}$ to $16.0 \mathrm {~mm}$ , what is the maximum potential difference through which the positive object moves? (k = 1/4πε₀ = 9.0 × 10⁹ N ∙ m²/C²)

Question

Quizplus · Accepted Answer

The maximum potential difference is when the positive object is at its farthest point from the negative point charge. At this point, the potential difference is:$$V = k\frac{q}{r} = (9.0 	imes 10^9 	ext{ N}\cdot	ext{m}^2/	ext{C}^2)\frac{6.9 	imes 10^{-6} 	ext{ C}}{16.0 	imes 10^{-3} 	ext{ m}} = 12 	ext{ MV}$$

A 69 μC Negative Point Charge Has a Positively Charged Particle