A tiny particle with charge + 5.0 μC is initially moving at 55 m/s.It is then accelerated through a potential difference of 500 V.How much kinetic energy does this particle gain during the period of acceleration?

Question

Quizplus · Accepted Answer

The kinetic energy gained by the particle is equal to the work done on it, which can be calculated using the formula $W = qV$, where $q$ is the charge (in coulombs) and $V$ is the potential difference (in volts). Substituting the given values, $W = 5.0 \times 10^{-6} \, \text{C} \times 500 \, \text{V} = 2.5 \times 10^{-3} \, \text{J}$.

A Tiny Particle with Charge + 5