A proton with a speed of 2.0 x 
M/s accelerates through a potential difference and thereby increases its speed to 4.0 × 
M/s.Through what magnitude potential difference did the proton accelerate? 
,mproton = 1.67 × 10-27 kg)
A) 630 V
B) 210 V
C) 840 V
D) 1,000 V
E) 100 V
Correct Answer:
Verified
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