A proton that is initially at rest is accelerated through an electric potential difference of magnitude 500 V.How much kinetic energy does it gain? (e = 1.60 × 10^-19C)

Question

Quizplus · Accepted Answer

The kinetic energy gained by the proton is equal to the electric potential energy change, which is given by the formula $KE = qV$, where $q$ is the charge of the proton (1.60 × 10^-19 C) and $V$ is the potential difference (500 V). Thus, $KE = 1.60 × 10^{-19} C \times 500 V = 8.0 × 10^{-17} J$.

A Proton That Is Initially at Rest Is Accelerated Through