A capacitor has a voltage of 391${~V}$ applied across its plates, and then the voltage source is removed. What is the potential difference across its plates if the space between them is then filled with mica, having a dielectric constant of 5.4?

Question

Quizplus · Accepted Answer

When a dielectric is inserted into a capacitor that has been disconnected from a voltage source, the potential difference across the plates decreases by a factor equal to the dielectric constant. Therefore, the new potential difference is 391 V / 5.4 = 72 V.

A Capacitor Has a Voltage of 391 V{~V} V Applied Across Its Plates, and Then the Voltage Source Is

A Capacitor Has a Voltage of 391 ${~V}$ Applied Across Its Plates, and Then the Voltage Source Is