A uniform electric field has the strength of $7.0 \mathrm {~N} / \mathrm { C }$ What is the electric energy density of this field? (ε₀ = 8.85 × 10^-12C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The electric energy density is given by the formula: 
$$\frac{1}{2}\epsilon_0 E^2$$
where $\epsilon_0$ is the electric constant and $E$ is the electric field strength. 
Substituting the given values, we get:
$$\frac{1}{2} \times 8.85 \times 10^{-12} \times (7.0)^2 = 2.2 \times 10^{-10}~\mathrm{J/m^3}$$
Thus, the answer is A: 2.2 × 10$^{-10}$ J/m$^3$.

A Uniform Electric Field Has the Strength Of 7.0 N/C7.0 \mathrm {~N} / \mathrm { C }7.0 N/C

A Uniform Electric Field Has the Strength Of $7.0 \mathrm {~N} / \mathrm { C }$