An 84-kW AM radio station broadcasts at 1000 kHz. How many photons are emitted each second by the transmitting antenna? (h = 6.626 × 10^-34 J ∙ s) A) 1.3 × $10^{32}$ B) 2.9 × $10^{24}$ C) 6.3 × $10^{12}$ D) 1.4 × $10^{15}$

Question

Quizplus · Accepted Answer

The energy of each photon is hf, where h is Planck's constant and f is the frequency. The power of the station is 84 kW, which is the total energy emitted per second. Therefore, the number of photons emitted per second is:$$N = \frac{P}{hf} = \frac{84 	imes 10^3 	ext{ W}}{(6.626 	imes 10^{-34} 	ext{ J s})(1000 	imes 10^3 	ext{ Hz})} = 1.3 	imes 10^{32}$$

An 84-KW AM Radio Station Broadcasts at 1000 KHz 103210^{32}1032 B) 29 ×

An 84-KW AM Radio Station Broadcasts at 1000 KHz $10^{32}$ B) 29 ×