The work function of a particular metal is $4.20 \times 10 ^ { - 19 } \mathrm {~J}$ What is the photoelectric cutoff (threshold) wavelength for this metal? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ∙ s) A) 473 nm B) 308 nm C) 393 nm D) 554 nm

Question

Quizplus · Accepted Answer

The cutoff wavelength ($\lambda_0$) can be calculated using the equation $\lambda_0 = \frac{hc}{\text{Work function}}$. Substituting the given values: $\lambda_0 = \frac{6.626 \times 10^{-34} \times 3.00 \times 10^8}{4.20 \times 10^{-19}}$, which gives approximately 473 nm.

The Work Function of a Particular Metal Is 4.20×10−19 J4.20 \times 10 ^ { - 19 } \mathrm {~J}4.20×10−19 J

The Work Function of a Particular Metal Is $4.20 \times 10 ^ { - 19 } \mathrm {~J}$