Find the de Broglie wavelength of a 1.30-kg missile moving at $28.10 \mathrm {~m} / \mathrm { s } \text {. }$ (h = 6.626 × 10^-34 J ∙ s) A) 1.81 × 10^-35 m B) 2.05 × 10^-35 m C) 2.28 × 10^-35 m D) 2.57 × 10^-35 m

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Quizplus · Accepted Answer

The de Broglie wavelength is given by the equation:$$\lambda = \frac{h}{p}$$where h is Planck's constant and p is the momentum of the object. The momentum of the missile is:$$p = mv = (1.30 \mathrm {~kg} )(28.10 \mathrm {~m} / \mathrm { s } ) = 36.53 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s }$$Substituting this into the equation for the de Broglie wavelength, we get:$$\lambda = \frac{6.626 	imes 10^{-34} \mathrm {~J} \cdot \mathrm { s } }{36.53 \mathrm {~kg} \cdot \mathrm { m } / \mathrm { s } } = 1.81 	imes 10^{-35} \mathrm {~m}$$Therefore, the correct answer is A.

Find the De Broglie Wavelength of a 1 28.10 m/s. 28.10 \mathrm {~m} / \mathrm { s } \text {. }28.10 m/s.

Find the De Broglie Wavelength of a 1 $28.10 \mathrm {~m} / \mathrm { s } \text {. }$