Rubidium $^{87}_{37}$ Rb is a naturally occurring isotope that undergoes β^- decay. What isotope is the product of this decay?

Name: Rubidium $^{87}_{37}$ Rb is a naturally occurring isotope that undergoes β - decay. What isotope is the product of this decay?
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Quizplus · Accepted Answer

In β^- decay, a neutron in the nucleus is converted into a proton, increasing the atomic number by 1 while the mass number remains the same. Therefore, $^{87}_{37}$Rb decays into $^{87}_{38}$Sr.

Rubidium 3787^{87}_{37}3787​ Rb Is a Naturally Occurring Isotope That Undergoes β- Decay

Rubidium $^{87}_{37}$ Rb Is a Naturally Occurring Isotope That Undergoes β^- Decay