Scandium $^{43}_{21}$Sc decays by emitting a positron. What isotope is the product of this decay?

Name: Scandium $^{43}_{21}$Sc decays by emitting a positron. What isotope is the product of this decay?
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The beta-positive decay of $^{43}_{21}$Sc results in the transformation of a proton into a neutron and the ejection of a positron. The resulting nucleus will therefore have one fewer proton and one more neutron than the starting nucleus, giving $^{44}_{20}$Ca.

Scandium 2143^{43}_{21}2143​ Sc Decays by Emitting a Positron 2143^{43}_{21}2143​ Sc B) 2145^{45}_{21}2145​ Sc C)

Scandium $^{43}_{21}$ Sc Decays by Emitting a Positron $^{43}_{21}$ Sc
B) $^{45}_{21}$ Sc
C)