Using the following equation for the combustion of octane,calculate the heat of reaction for 100.0 g of octane.The molar mass of octane is 114.33 g $\mathrm { mol } ^ { - 1 }$ . 2C₈H₁₈ + 25O₂ ? 16CO₂ + 18H₂O
D_rH°= -11018 kJ

Question

Using the following equation for the combustion of octane,calculate the heat of reaction for 100.0 g of octane.The molar mass of octane is 114.33 g

\mathrm { mol } ^ { - 1 }

. 2C₈H₁₈ + 25O₂ ? 16CO₂ + 18H₂O
D_rH°= -11018 kJ

Quizplus · Accepted Answer

The heat of reaction for 100.0 g of octane is calculated by first determining the moles of octane (100.0 g / 114.33 g/mol = 0.874 mol), then using the given reaction enthalpy (-11018 kJ for 2 moles of octane) to find the heat for 0.874 moles: (0.874 mol / 2 mol) × -11018 kJ = -4820.37 kJ, which is approximately 4.82 × 10³ kJ.

Using the Following Equation for the Combustion of Octane,calculate the Heat