Using the following equation for the combustion of octane,calculate the amount of moles of oxygen that reacts with 100.0 g of octane.The molar mass of octane is 114.33 g $\mathrm { mol } ^ { - 1 }$ .The molar mass of carbon dioxide is 44.0095 g $\mathrm { mol } ^ { - 1 }$ . 2C₈H₁₈ + 25O₂ ? 16CO₂ + 18H₂O
D_rH°= -11018 kJ

Question

Using the following equation for the combustion of octane,calculate the amount of moles of oxygen that reacts with 100.0 g of octane.The molar mass of octane is 114.33 g

\mathrm { mol } ^ { - 1 }

.The molar mass of carbon dioxide is 44.0095 g

\mathrm { mol } ^ { - 1 }

. 2C₈H₁₈ + 25O₂ ? 16CO₂ + 18H₂O
D_rH°= -11018 kJ

Quizplus · Accepted Answer

First, calculate the moles of octane: 100.0 g / 114.33 g/mol = 0.874 moles. According to the balanced equation, 2 moles of octane react with 25 moles of oxygen. Therefore, 0.874 moles of octane will react with (0.874 moles * 25/2) = 10.93 moles of oxygen.

Using the Following Equation for the Combustion of Octane,calculate the Amount