Chocolates
A box of chocolates contains 18 pieces,10 of which have nuts while the remaining 8 do not.Four pieces are chosen at random.
-What is the probability that exactly 2 pieces have nuts?
A) 0.412
B) 0.564
C) 0.681
D) 0.750
E) 0.833

Question

Quizplus · Accepted Answer

The probability of choosing exactly 2 pieces with nuts can be calculated using combinations. The number of ways to choose 2 pieces with nuts out of 10 is $C(10,2)$, and the number of ways to choose 2 pieces without nuts out of 8 is $C(8,2)$. The total number of ways to choose 4 pieces out of 18 is $C(18,4)$. Thus, the probability is $\frac{C(10,2) \times C(8,2)}{C(18,4)} = \frac{45 \times 28}{3060} = 0.412$.

Chocolates A Box of Chocolates Contains 18 Pieces,10 of Which Have