Chocolates
A box of chocolates contains 18 pieces,10 of which have nuts while the remaining 8 do not.Four pieces are chosen at random.
-What is the probability that at least 3 pieces have nuts?
A) 0.051
B) 0.118
C) 0.169
D) 0.242
E) 0.382

Question

Quizplus · Accepted Answer

The probability of choosing a piece with nuts is 10/18, and the probability of choosing a piece without nuts is 8/18. The probability of choosing at least 3 pieces with nuts is the complement of the probability of choosing 0, 1, or 2 pieces with nuts. The probability of choosing 0 pieces with nuts is (8/18)^4, the probability of choosing 1 piece with nuts is 4 * (10/18) * (8/18)^3, and the probability of choosing 2 pieces with nuts is 6 * (10/18)^2 * (8/18)^2. Therefore, the probability of choosing at least 3 pieces with nuts is 1 - (8/18)^4 - 4 * (10/18) * (8/18)^3 - 6 * (10/18)^2 * (8/18)^2 = 0.382.

Chocolates A Box of Chocolates Contains 18 Pieces,10 of Which Have