An object of mass of 2.0 kg hangs from an ideal massless spring with a spring constant of 50 N/m.An oscillating force F = (4.8 N)cos[(3.0 rad/s)t] is applied to the object.What is the amplitude of the resulting oscillations? You can neglect damping.
A) 0.15 m
B) 0.30 m
C) 1.6 m
D) 2.4 m
E) 0.80 m

Question

Quizplus · Accepted Answer

The amplitude of the oscillations can be found using the formula for the amplitude of a driven harmonic oscillator: A = F₀ / |k - mω²|, where F₀ is the amplitude of the driving force, k is the spring constant, m is the mass, and ω is the angular frequency of the driving force. Substituting the given values, A = 4.8 N / |50 N/m - (2.0 kg)(3.0 rad/s)²| = 0.15 m.

An Object of Mass of 2