What is the net power that a person loses through radiation if her surface area is 1.20 m²,if her emissivity is 0.895,if her skin temperature is 300 K,and if she is in a room that is at a temperature of 17°C? The Stefan-Boltzmann constant is 5.670 × 10^-8 W/m² • K⁴. A) 60.3 W B) 62.6 W C) 65.7 W D) 68.4 W E) 64.8 W

Question

Quizplus · Accepted Answer

The net power that a person loses through radiation can be found using the Stefan-Boltzmann Law:

P = εσAT^4

Where P is the net power, ε is the emissivity, σ is the Stefan-Boltzmann constant, A is the surface area, and T is the absolute temperature.

Converting the skin temperature to absolute temperature:

T = 300 K

Converting the room temperature to absolute temperature:

T_room = 17°C + 273.15 = 290.15 K

Substituting the given values:

P = 0.895 × 5.670 × 10^-8 × 1.20 × (300)^4 - 0.895 × 5.670 × 10^-8 × 1.20 × (290.15)^4

Solving for P:

P = 62.6 W

Therefore, the person loses a net power of 62.6 W through radiation.

What Is the Net Power That a Person Loses Through