A hydrogen atom initially in the n = 6 state decays to the n = 2 state.The emitted photon is detected in a photographic plate.What is the wavelength of the detected photon? The lowest level energy state of hydrogen is -13.6 eV.(h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19 J, A) 410 nm B) 93.8 nm C) 1090 nm D) 93.1 nm

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The Answer of A hydrogen atom initially in the n = 6 state decays to the n = 2 state.The emitted photon is detected in a photographic plate.What is the wavelength of the detected photon? The lowest level energy state of hydrogen is -13.6 eV.(h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19 J, A) 410 nm B) 93.8 nm C) 1090 nm D) 93.1 nm

A Hydrogen Atom Initially in the N = 6 State