An 84-kW AM radio station broadcasts at 1000 kHz . How many photons are emitted each second by the transmitting antenna? (h = 6.626 × 10^-34 J ∙ s) A) 1.3 × 10³² B) 2.9 × 10²⁴ C) 6.3 × 10¹² D) 1.4 × 10¹⁵

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Quizplus · Accepted Answer

The energy of one photon is given by E = hν, where ν is the frequency. For 1000 kHz, ν = 1000 × 10^3 Hz. The energy per photon is E = 6.626 × 10^-34 J ∙ s × 1000 × 10^3 Hz = 6.626 × 10^-28 J. The total power is 84 kW = 84 × 10^3 J/s. The number of photons emitted per second is the total power divided by the energy per photon: (84 × 10^3 J/s) / (6.626 × 10^-28 J/photon) ≈ 1.3 × 10^32 photons/s.

An 84-KW AM Radio Station Broadcasts at 1000 KHz