In a room where g = 9.81 m/s²,a hockey puck slides off the edge of a platform with an initial velocity of 28.0 m/s horizontally.The height of the platform above the ground is 2.00 m.What is the speed of the puck just before it hits the ground? Ignore air. A)48.2 m/s B)28.7 m/s C)28.0 m/s D)26.3 m/s E)6.26 m/s

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Quizplus · Accepted Answer

The horizontal velocity remains constant at 28.0 m/s. The vertical velocity can be found using v = sqrt(2gh) = sqrt(2*9.81*2) = 6.26 m/s. The resultant speed is sqrt((28.0)^2 + (6.26)^2) = 28.7 m/s.

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