An ideal reversible thermodynamic pump is taking heat from the outside air at -10.0°C and discharging it into the house at 18.0°C.What is the coefficient of performance of this thermodynamic pump?

Question

Quizplus · Accepted Answer

The coefficient of performance of a thermodynamic pump is given by the ratio of the heat output to the work input. For a reversible pump, the work input is equal to the difference in heat output and heat input. Therefore, the coefficient of performance is given by:COP = Q_out / (Q_out - Q_in)where Q_out is the heat output and Q_in is the heat input.In this problem, the heat output is 18.0°C and the heat input is -10.0°C. Therefore, the coefficient of performance is:COP = 18.0°C / (18.0°C - (-10.0°C)) = 10.4

An Ideal Reversible Thermodynamic Pump Is Taking Heat from the Outside