When 1.0 kg of steam at 100°C condenses to water at 100°C,what is the change in entropy of the steam? The latent heat of vaporization of water is 22.6 × 10⁵ J/kg.

Question

Quizplus · Accepted Answer

When steam at 100°C condenses to water at 100°C, the change in entropy can be calculated using the formula:
ΔS = Q/T
Where ΔS is the change in entropy, Q is the heat transferred, and T is the temperature.
The heat transferred is the latent heat of vaporization of water, which is given as 22.6 × 10¹⁵ J/kg. The temperature remains constant at 100°C.
Therefore, ΔS = 22.6 × 10¹⁵ J/kg / 373.15 K = -6.1 × 10¹³ J/K.
Since the steam is undergoing a process where it loses its organization, the change in entropy is negative, so the answer is C.

When 10 Kg of Steam at 100°C Condenses to Water at at 100°C,what