Consider a uniform horizontal $\vec { E }$ field of 50 N/C directed toward the east.If the electric potential at a given point in the field is 80 V,what is the potential at a point 1.0 m directly east of the point?

Question

Quizplus · Accepted Answer

The potential difference is given by $ \Delta V = -E \cdot d $, where $ E = 50 \, \text{N/C} $ and $ d = 1.0 \, \text{m} $. Thus, $ \Delta V = -50 \times 1 = -50 \, \text{V} $. The potential at the new point is $ 80 \, \text{V} - 50 \, \text{V} = 30 \, \text{V} $.

Consider a Uniform Horizontal E⃗\vec { E }E Field of 50 N/C Directed Toward the East

Consider a Uniform Horizontal $\vec { E }$ Field of 50 N/C Directed Toward the East