The potential difference between the plates of an ideal air-filled parallel-plate capacitor with a plate separation of 6.0 cm is 60 V.What is the magnitude of the $\vec { E }$ field between the plates of this capacitor?

Question

Quizplus · Accepted Answer

The electric field between the plates of a parallel-plate capacitor is given by the equation E = V/d, where V is the potential difference and d is the distance between the plates. Plugging in the given values, we get E = 60 V / 0.06 m = 1000 V/m. Therefore, the answer is (C).

The Potential Difference Between the Plates of an Ideal Air-Filled E⃗\vec { E }E

The Potential Difference Between the Plates of an Ideal Air-Filled $\vec { E }$