An ideal air-filled parallel-plate capacitor with horizontal plates has a plate separation of 5.0 cm.If the potential difference between the plates is 2000 V,with the top plate at the higher potential,what are the magnitude and direction of the $\vec { E }$ field between the plates?

Question

Quizplus · Accepted Answer

The electric field $\vec{E}$ between the plates of a parallel-plate capacitor is given by $E = \frac{V}{d}$, where $V$ is the potential difference and $d$ is the separation between the plates. Here, $E = \frac{2000 \, \text{V}}{0.05 \, \text{m}} = 40000 \, \text{N/C}$. The field direction is from the higher potential to the lower potential, which is downward.

An Ideal Air-Filled Parallel-Plate Capacitor with Horizontal Plates Has a Plate