When the potential difference between the plates of an ideal air-filled parallel plate capacitor is 35 V,the $\vec { E }$ field between the plates is 750 V/m.If the plate area is 4.0 × 10^-2 m²,what is the capacitance of this capacitor? (ε₀ = 8.85 × 10^-12C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The capacitance of a parallel plate capacitor is given by:
\begin{align*}
C &= \frac{\epsilon_0 A}{d}\
&= \frac{(8.85	imes 10^{-12} 	ext{ F/m}) (4.0 	imes 10^{-2}	ext{ m}^2)}{(750 	ext{ V/m})}\
&= 7.6 	imes 10^{-12} 	ext{ F}
\end{align*}

When the Potential Difference Between the Plates of an Ideal E⃗\vec { E }E

When the Potential Difference Between the Plates of an Ideal $\vec { E }$