A capacitor has a voltage of $391 \mathrm {~V}$ applied across its plates,and then the voltage source is removed.What is the potential difference across its plates if the space between them is then filled with mica,having a dielectric constant of 5.4?

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Quizplus · Accepted Answer

When a dielectric material with a dielectric constant (k) is introduced between the plates of a capacitor, the potential difference across the plates decreases by a factor equal to the dielectric constant. The new voltage $V'$ can be found using the formula $V' = V/k$, where $V$ is the original voltage and $k$ is the dielectric constant. Therefore, $V' = 391V / 5.4 ≈ 72V$.

A Capacitor Has a Voltage Of 391 V391 \mathrm {~V}391 V Applied Across Its Plates,and Then the Voltage Source Is Removed

A Capacitor Has a Voltage Of $391 \mathrm {~V}$ Applied Across Its Plates,and Then the Voltage Source Is Removed