What is the momentum of a photon of light that has a wavelength of 480 nm? $( h = 6.626 \times 10 ^{- 34} \mathrm {~J} \cdot \mathrm { s } )$
A)1.1 × $10^{ - 27}$ kg∙m/s
B)2.2 × $10^{ - 27}$ kg∙m/s
C)1.8 × $10^{ - 27}$ kg∙m/s
D)1.4 × $10^{ - 27}$ kg∙m/s
E)2.0 × $10 ^{- 27}$ kg∙m/s

Question

Quizplus · Accepted Answer

The momentum $p$ of a photon can be calculated using the formula $p = \frac{h}{\lambda}$, where $h$ is Planck's constant and $\lambda$ is the wavelength of the photon. Substituting the given values, $p = \frac{6.626 \times 10^{-34} \, \text{J} \cdot \text{s}}{480 \times 10^{-9} \, \text{m}} = 1.38 \times 10^{-27} \, \text{kg} \cdot \text{m/s}$, which rounds to $1.4 \times 10^{-27} \, \text{kg} \cdot \text{m/s}$.

What Is the Momentum of a Photon of Light That (h=6.626×10−34 J⋅s)( h = 6.626 \times 10 ^{- 34} \mathrm {~J} \cdot \mathrm { s } )(h=6.626×10−34 J⋅s)

What Is the Momentum of a Photon of Light That $( h = 6.626 \times 10 ^{- 34} \mathrm {~J} \cdot \mathrm { s } )$