Assuming that the temperature and quantity of a gas sample remain constant, what will be the final pressure of a 1.6 L sample of a gas originally at 330 K and 4.84 atm, when the volume is reduced
To 840 mL?

Question

Quizplus · Accepted Answer

According to Boyle's Law (P1V1 = P2V2), if the temperature and quantity of gas remain constant, the pressure is inversely proportional to the volume. Given P1 = 4.84 atm, V1 = 1.6 L, and V2 = 0.84 L, the final pressure P2 can be calculated as P2 = (P1 * V1) / V2 = (4.84 atm * 1.6 L) / 0.84 L = 9.22 atm.

Assuming That the Temperature and Quantity of a Gas Sample