Consider the reaction CuSO₄(s)$\rightarrow$ CuO(s)+ SO₃(g) If $\Delta$G $\circ$ = -14.6 kJ at 950 $\circ$ C for this reaction,what is $\Delta$G for an SO₃(g)pressure of 20 bar at this temperature.

Question

Quizplus · Accepted Answer

The change in Gibbs free energy ($\Delta G$) for a reaction under non-standard conditions can be calculated using the equation $\Delta G = \Delta G^\circ + RT \ln Q$, where $Q$ is the reaction quotient. Here, $\Delta G^\circ = -14.6 \text{ kJ}$, $R = 8.314 \times 10^{-3} \text{ kJ/mol K}$, $T = 950 + 273 = 1223 \text{ K}$, and $Q = P_{SO_3} = 20 \text{ bar}$. Calculating $\Delta G$ gives approximately 15.9 kJ.

Consider the Reaction CuSO4(s) →\rightarrow→ CuO(s)+ SO3(g) If Δ\DeltaΔ G ∘\circ∘ = -14

Consider the Reaction
CuSO₄(s) $\rightarrow$ CuO(s)+ SO₃(g)
If $\Delta$ G^$\circ$ = -14