How many moles of O₂(g)are produced by electrolysis of Na₂SO₄(aq)if 0.120 A is passed through the solution for 65.0 min?

Question

Quizplus · Accepted Answer

The correct answer is A because the number of moles of O2(g) produced by electrolysis of Na2SO4(aq) can be calculated using Faraday's law of electrolysis. The amount of charge passed through the solution is Q = It = (0.120 A)(65.0 min)(60 s/min) = 468 C. According to Faraday's law, the number of moles of O2(g) produced is n = Q/nF, where n is the number of electrons transferred per molecule of O2(g) and F is the Faraday constant (96,485 C/mol). For the electrolysis of Na2SO4(aq), n = 4 and F = 96,485 C/mol, so n = 468 C / (4 mol * 96,485 C/mol) = 0.00121 mol.

How Many Moles of O2(g)are Produced by Electrolysis of Na2SO4(aq)if

How Many Moles of O₂(g)are Produced by Electrolysis of Na₂SO₄(aq)if