Consider the reaction 2N₂O₅(g)$\rightarrow$ 4NO₂(g)+ O₂(g) Rate = k[N₂O₅] If the initial concentration of N₂O₅ is 0.80 M,the concentration after 5 half-lives is

Question

Quizplus · Accepted Answer

The reaction is first order with respect to [N₂O₅], so the concentration will decrease by a factor of 2 after each half-life. After 5 half-lives, the concentration will decrease by a factor of (2)^5 = 32. 0.80 M / 32 = 0.025 M, which is the concentration after 5 half-lives. Therefore the correct answer is B.

Consider the Reaction 2N2O5(g) →\rightarrow→ 4NO2(g)+ O2(g) Rate = K[N2O5] If the Initial Concentration of

Consider the Reaction 2N₂O₅(g) $\rightarrow$ 4NO₂(g)+ O₂(g)
Rate = K[N₂O₅]
If the Initial Concentration of