Consider the Reaction
NOBr(g) $\rightarrow$ NO(g)+ ½Br₂(g)
a Plot of [NOBr]^-1 Vs T Gives a of [NOBr]^-1

Consider the reaction
NOBr(g) $\rightarrow$ NO(g) + ½Br₂(g)
A plot of [NOBr]^-1 vs t gives a straight line with a slope of 2.00 M^-1.s^-1.The order of the reaction and the rate constant,respectively,are

A) second-order and 0.500 M^-1.s^-1
B) first-order and 2.00 s^-1
C) second-order and 2.00 M^-1.s^-1
D) first-order and 0.241 s^-1.
E) second-order and 16.6 M^-1.s^-1