Suppose that the first goal in a GP problem is to make 3 X₁ + 4 X₂ approximately equal to 36.Using the deviational variables d₁^? and d₁⁺,the following constraint can be used to express this goal. 3 X₁ + 4 X₂ + d₁^? ? d₁⁺ = 36 If we obtain a solution where X₁ = 6 and X₂ = 2,what values do the deviational variables assume? A)$\mathrm{d}_{1}^{-}=0, \mathrm{~d}_{1}^{+}=10$ B)$\mathrm{d}_{1}^{-}=10, \mathrm{~d}_{1}^{+}=0$ C)$\mathrm{d}_{1}^{-}=5, \mathrm{~d}_{1}^{+}=5$ D)$\mathrm{d}_{1}^{-}=6, \mathrm{~d}_{1}^{+}=0$

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Quizplus · Accepted Answer

The expression 3X₁ + 4X₂ = 36 becomes 3(6) + 4(2) = 26. To make it equal to 36, we need to add 10, so d₁⁻ = 10 and d₁⁺ = 0.

Suppose That the First Goal in a GP Problem Is d1−=0, d1+=10\mathrm{d}_{1}^{-}=0, \mathrm{~d}_{1}^{+}=10d1−​=0, d1+​=10

Suppose That the First Goal in a GP Problem Is $\mathrm{d}_{1}^{-}=0, \mathrm{~d}_{1}^{+}=10$