How many milliliters of 0.200 M FeCl₃ are needed to react with an excess of Na₂S to produce 0.690 g of Fe₂S₃ if the percent yield for the reaction is 65.0%? 3 Na₂S(aq)+ 2 FeCl₃(aq)→ Fe₂S₃(s)+ 6 NaCl(aq) A) 12.8 mL B) 21.6 mL C) 25.5 mL D) 51.1 mL

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The Answer of How many milliliters of 0.200 M FeCl₃ are needed to react with an excess of Na₂S to produce 0.690 g of Fe₂S₃ if the percent yield for the reaction is 65.0%? 3 Na₂S(aq)+ 2 FeCl₃(aq)→ Fe₂S₃(s)+ 6 NaCl(aq) A) 12.8 mL B) 21.6 mL C) 25.5 mL D) 51.1 mL

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